9x^2+100x-6000=0

Solution for 9x^2+100x-6000=0 equation:

9x^2+100x-6000=0

a = 9; b = 100; c = -6000;
Δ = b2-4ac
Δ = 1002-4·9·(-6000)
Δ = 226000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{226000}=\sqrt{400*565}=\sqrt{400}*\sqrt{565}=20\sqrt{565}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{565}}{2*9}=\frac{-100-20\sqrt{565}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{565}}{2*9}=\frac{-100+20\sqrt{565}}{18}
$